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Table 5 Results from regression analysis

From: Do holes in long-lasting insecticidal nets compromise their efficacy against pyrethroid resistant Anopheles gambiae and Culex quinquefasciatus? Results from a release–recapture study in experimental huts

Outcome

Var.

Model

McFadden’s pseudo R2

Difference

Fed

2

Species + Type + Species:Type

0.345

 

3

Species + logTHSp1 + Type + Species:Type + Species:logTHSp1

0.928

0.583*

4

Species + logTHSp1 + Type + Size + Species:Type + Species:Size + logTHSp1:Size + Species:logTHSp1 + logTHSp1:Type + Species:logTHSp1:Size

0.979

0.051*

Dead

2

Species + Type + Species:Type

0.979

 

3

Species + logTHSp1 + Type + Species:Type + Species:logTHSp1

0.980

0.001

4

Species + logTHSp1 + Type + Size + Species:Type + Species:logTHSp1 + Species:Size + logTHSp1:Size

0.989

0.009*

Veranda

2

Species + Type + Species:Type

0.652

 

3

Species + logTHSp1 + Type + Species:Type + Species:logTHSp1

0.762

0.110*

4

Species + logTHSp1 + Type + Size + Species:Type + Species:logTHSp1 + Type:Size + logTHSp1:Size + Species:Size + Species:Type:Size

0.887

0.125*

Under net

2

Species + Type + Species:Type

0.398

 

3

Species + logTHSp1 + Type + Species:Type + logTHSp1:Type + Species:logTHSp1 + Species:logTHSp1:Type

0.739

0.341*

4

Species + logTHSp1 + Type + Size + logTHSp1:Size + Species:Type + logTHSp1:Type + Species:logTHSp1 + Species:Size + Type:Size + Species:logTHSp1:Size + logTHSp1:Type:Size + Species:Type:Size

0.945

0.206*

  1. Var.: number of explanatory variables considered, with two variables these are Species and Type (of net), with three variables the variable logTHSp1 (log of total holed surface area in cm2 plus 1) is added, and with four variables the variable (hole) Size is added; terms in bold face: term added compared to less complex model; terms in italic: term removed in more complex model; two variables separated by ‘:’ indicate an interaction term; differences marked with an asterisk (*) are significantly different (likelihood ratio test, alpha = 0.05).